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Fit one decode replica before buying more HBM — conditional result

About 180 GB resident; 40 ms memory lower bound. At most 9 sequences fit; 10 fail. Below about 3.2 TB/s the 50 ms memory budget fails.derived

Value kindderived — Derived values are guide calculations; their result is only as fixed as the stated inputs, scope, and method.
ScopeWeights = 70×10⁹ × 2 B = 140 GB. Define K = 2 × 80 × 8 × 128 × 2 B × 8,192, the exact KV bytes per sequence. Eight sequences need about 21 GB of KV; with 20 GB reserve, the resident set is about 180 GB. Capacity screen: floor((186−140−20)×10⁹/K) = 9 sequences. At nine, total residence is below 185 GB; at ten it is above 186 GB (about 187 GB), so the integer decision uses exact tensor counts rather than rounded totals. Reading weights and KV at 4.0 TB/s takes about 40 ms before compute and collectives. The 50 ms bandwidth boundary is (140×10⁹+8K)/0.050, about 3.2 TB/s; the unrounded inequality governs. At 3.0 TB/s memory alone takes about 54 ms and fails.
As of2026-09
SourceNVIDIA GB200 specifications and CUDA performance memory model — method reference; guide-authored hypothetical scenario September 8, 2026. No supplier quote or test measurement.
DerivationWeights = 70×10⁹ × 2 B = 140 GB. Define K = 2 × 80 × 8 × 128 × 2 B × 8,192, the exact KV bytes per sequence. Eight sequences need about 21 GB of KV; with 20 GB reserve, the resident set is about 180 GB. Capacity screen: floor((186−140−20)×10⁹/K) = 9 sequences. At nine, total residence is below 185 GB; at ten it is above 186 GB (about 187 GB), so the integer decision uses exact tensor counts rather than rounded totals. Reading weights and KV at 4.0 TB/s takes about 40 ms before compute and collectives. The 50 ms bandwidth boundary is (140×10⁹+8K)/0.050, about 3.2 TB/s; the unrounded inequality governs. At 3.0 TB/s memory alone takes about 54 ms and fails.
Reviewchecking…review by 2027-03-08 · standard cadence
Recorded changeslast 2026-09-16
Claim idguide2-t29-7-6-result

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